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Resistances R,, R, R, and R, are
connected as shown in the figure. Si
and S2 are two keys. Discuss the
current flowing in the circuit in the
following cases.
a. Both S and S, are closed.
b. Both S and S, are open.
c. S is closed but S, is open.
Answers
Answer:
Sry for being to messing:(
Explanation:
• a) Here, R1 and R2 are in parallel. Their effective resistance is R'= R1 x R2/R1 + R2.
•Also, R4 is in parallel with a conductor of 0 resistance. Their equivalent resistance is therefore 0.
•Now, R' and R3 are in series. Thus, the equivalent resistance of the circuit is R,eq= (R1 x R2/R1 + R2) + R3.
== R1xR2 + R1xR3 + R3xR2/ R1+R2.
•Hence, the current flowing in the circuit is
I=V//R1 R2+R1 R3+R3 R2// R1+R2=V(R1+R2)//R1 R2+R1 R3+R3 R2.
• b) Here, R1, R4 and R3 are in series. Therefore, the equivalent resistance of the circuit is
R,eq=R1+R2+R3
•Hence, the current flowing in the circuit is
I=V//Req=V//R1+R2+R3
where, V is the potential difference of the battery.
• c) Here, R1 and R2 are in parallel. Their effective resistance is
R'=R1×R2R1+R2
• Now, R3, R' and R4 are in series. Thus, the equivalent resistance of the circuit is
Req=(R1×R2//R1+R2)+R3+R4=R1R2+R1R3+R3R2+R1R4+R4R2R1+R2.
• Hence, the current flowing in the circuit is
I=V//R1R2+R1R3+R3R2+R1R4+R4R2//R1+R2=V(R1+R2)//R1R2+R1R3+R3R2+R1R4+R4R2
where, V is the potential difference of the battery.
I hope it helps.
Answer:
1 ➝ R4 is stunted by S2. Hence the resistance of this combination will be practically zero.
= 1 1 1
__ =__ + __
Rp R1 R2
Rp = R1 R2
______
R1 + R2
R3 and Rp in series :
= Rs = R3 + Rp
= I3 = V
______
R3 + Rs
V1 = V - I3 R3
R3 V R3
V - _____ = V (______)
R3 + Rp R3 + Rp
= V Rp
(______)
R3 + Rp
= I1 = V1 V Rp
___ =___ (______)
R1 R1 R3 + Rp
Similarly,
I2 = V Rp
__ (______)
R2 R3 + Rp
Explanation:
Hope it will help you ✍️
