Question

(w the cost of 1 pencil is 85 paisa. Find the cost of 5 such pencil.
(IT) the cost of 4 pen is Rs 28, Find the cost of 1 pen.
(iv) Find the perimeter of rectangle whose length = 40 cm and breadth = 22cm.
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Answer 1

Answer:

i. cost of one pencil = 85 paise.

cost of 5 pencil =85×5= 425 paise.

cost of 5 pencil =425 paise or 4.25 paise.

ii. cost of 4 pen = 28 rupees.

cost of 1 pen =28÷4=7 rupees.

cost of 1 pen =7rupees.

iii. perimeter of rectangle =2(length+breadth).

length =40cm.

breadth=22cm.

perimeter = 2(40+22)cm.

84cm.

Hence , perimeter of rectangle =84cm.

Answer 2

ANSWERS

Question

The cost of 1 pencil is 85 paisa. Find the cost of 5 such pencil.

Answer

Cost of one pencil = 85 paise

Cost of 5 such pencils = 5 × 85paise = 425 paise = ₹ 4.25

$\red\bigstar$ Cost of 5 such pencils = 425 paise = ₹ 4.25

Question

The cost of 4 pen is Rs 28, Find the cost of 1 pen .

Answer

Cost of 4 pens = ₹ 28.

$\sf Cost \: of \: 1 \: such\: pen = \dfrac{28}{4}$

$\blue\bigstar$ Cost of 1 such pen = ₹ 7.

Question

Find the perimeter of rectangle whose length = 40 cm and breadth = 22cm.

Answer

Length(l) of the rectangle = 40cm.

Breadth(b) of the rectangle = 22cm.

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 40 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 22 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Perimeter of the rectangle = 2(l+b)

Here,

Length(l) = 40cm.

Breadth(b) = 22cm.

Perimeter of the rectangle = 2(40+22)

$\implies$ Perimeter of the rectangle = 2 × 62

$\implies$Perimeter of the rectangle = 124 cm.

$\bigstar$ Perimeter of the rectangle = 124 cm.