W Try These a 1. A bus started its journey and reached different places with a speed of 60 km/hour. The journey is shown on page 14. (1) Find the total distance covered by the bus from A to D. sama (ii) Find the total distance covered by the bus from D to G. (iii) Find the total distance covered by the bus, if it starts from A and returns back to A. (iv) Can you find the difference of distances from C to D and D to E?
Answers
Answer :-
Total distance from A to D = AB + BC + CD
= (4170 + 3410 + 2160) km = 9740 km
(ii) Total distance between D to G = DE + EF + FG
= (8140 + 4830 + 2550) km = 15520 km
(iii) Required distance = AD + DG + GA
= (4170 + 3410 + 2160 + 8140 + 4830 + 2550 + 1290) km = 26550 km
(iv) The difference of distances from C to D and D to E = (8140 - 2160) km = 5980 km.
It will help you.
Step-by-step explanation:
You missed the attachment so I'm adding the bus journey picture.
i) The total distance covered by the bus from A to D
= (4170 + 3410 + 2160) km
= 9740 km
ii) The total distance covered by the bus from D to G
= (8140 + 4830 + 2550) km
= 15520 km
iii) The total distance covered by the bus, if it starts from A and returns back to A
= (4170 + 3410 + 2160 + 8140 + 4830 + 2550 + 1290) km
= 26550 km
iv) The difference of distances from C to D and D to E
= (8140 - 2160) km
= 5980 km
v) Speed of the bus = 60 km/h
Time taken = (Distance)/60 hours
a) The distance between A to B
= 4170 km
Time taken
= 4170/60 hours
= 4170/60 × 60 minutes
= 4170 minutes
= (60 × 69) + 30 minutes
= 69 hours 30 minutes
b) The distance between C to D
= 2160 km
Time taken
= 2160/60 hours
= 36 hours
c) The distance between E to G
= (4830 + 2550) km
= 7380 km
Time taken
= 7380/60 km
= 123 hours
d) Total journey
= 26550 km
Time taken
= 26550/60 hours
= 442.5 hours
= 442 hours 30 minutes