Math, asked by snehaiitian, 9 months ago

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The roots of the equation (b - c) x2 + (c-a) x + (a - b) = 0 are
с-а
b-C
(A)
(B) a-b
b-cl
b -C
ab'
(D)
2.1

Answers

Answered by aka01
0

The roots of the equation (b - c) x2 + (c-a) x + (a - b) = 0 are

с-а

b-C

(A)

(B) a-b

b-cl

b -C

ab'

(D)

2.1

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