Chemistry, asked by dangerunq, 9 months ago

w/w) of ethylene guyeol (GHG] in aqueous
solution [solvent is H2o] is zo. Calculate mole
fraction of ethylene glycol (0.067]

Answers

Answered by sujalnagar762

Answer:

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calculate the mole fraction ethylene glycol {C2H6O2} and water in a solution containing 20% of C2H6O2 by mass

Asked by Vivek Chandravanshi | 26th Oct, 2014, 01:33: PM

Expert Answer:

20% of C2H6O2 by mass is present.

That means solution has 20 g of ethylene glycol and 80 g of water.

Now,

Molar mass of C2H6O2 = 12 x 2 + 1 x 6 + 2 x 16 = 62 g mol-1 .

Moles of C2H6O2 = 20 / 62 = 0.322 moles

Moles of water = 80 / 18 = 4.444 moles

Mole fraction of ethylene glycol = 0.322 / 0.322 + 4.444 = 0.068

Mole fraction of water = 1 - 0.068 = 0.932

Explanation:

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