Question

W1 is a window against which a ladder 8.5m long rests.The height of the window is 7.5m from the ground without moving the bottom of the ladder, it is turned around to rest against a window w2 on the opposite wall.If the height of window w2 is 4m above the ground ,find the distance between the walls.

Answer 1

let h=8.5
p=7.5
b= w1
then
$b {}^{2} = h {}^{2} - p {}^{2}$
= (8.5)^2 - ( 7.5 )^2
= 272. 25 - 56 125
= 16
then b^2 = 16
b =
$\sqrt{16}$
= 4
so , w1 = 4 m

2nd
w2 = b
h = 8.5m
p = 4 m
then b^2 = h ^2 - p^2
= (8.5)^2 - 4^2
= 72.25 - 16
= 56.25
b =
$\sqrt{56.25}$
b= 7.5
so , w2 = 7.5 m

Answer 2

Answer:

the answer is 11.5

the adittion of sum gives the answer