Physics, asked by amardeep9842, 1 year ago

W14A force of magnitude 2N extends a spring by 0.3 m. If the spring obeys Hooke law.
then a force of 6N will extend it by
(A) 0.1 m
(B) 0.3 m
(C) 0.6 m
(D) 0.9 m​

Answers

Answered by tiwaavi
1

Answer ⇒ Option (d). 0.9 m.

Explanation ⇒ ∴ Since, the spring obeys Hook's law.

''This means extension produced in the spring will be directly proportional to the force. (As what said by the Hooke's law.)''

∴ x ∝ F

∴ x = kF, where k is constant of Hooke's law.

∴ k = x/F

∴ k = 0.3/2

Now, when a force of 6 N is applied, then k = x/6

Now, k being an constant will remains same.

∴ x/6 = 0.3/2

∴ x = 0.9 m.

Hence, option (d). is correct.

Hope it helps.

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