Math, asked by hriarea17, 6 months ago

w²+13w+12=0 please help​

Answers

Answered by Anonymous
1

Answer:

w= -1

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Step-by-step explanation:

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Answered by anindyaadhikari13
2

Correct Question:-

➡ Solve the following quadratic equation and find it's root.

Answer:-

➡ The roots of the given equation are -1 and -12 respectively.

Solution:-

Given equation,

➡ w² +13w + 12 = 0

➡ w² + w + 12w + 12 = 0

Taking w as common,

➡ w(w + 1) + 12(w + 1) = 0

➡ (w + 1)(w + 12) = 0

By zero product rule,

➡ Either w + 1 = 0 or w + 12 = 0

So,

➡ w + 1 = 0

➡ w = -1

Also,

➡ w + 12 = 0

➡ w = -12

Hence, the roots of the given quadratic equation are -1 and -12 respectively.

Verification:-

➡ Let us verify our result.

When w = -1

w² + 13w + 12

= (-1)² + 13×(-1) + 12

= 1 - 13 + 12

= -12 + 12

= 0

➡ Hence, -1 is a solution.

Again,

When w = -12.

w² + 13w + 12

= (-12)² + 13×(-12) + 12

= 144 - 156 + 12

= -12 + 12

= 0

So, -12 is also a solution.

Hence, -1 and -12 are roots of the given quadratic equation (Verified)

Note:-

➡ Zero Product rule says that if a and b are two numbers of expression such that ab=0 then either a = 0 or b = 0 or both a and b equal to 0.

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