Question

wach side of an equilateral measures 10 cm then area of traingle is​

Answer 1

Answer:

step by step explanation

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\sqrt{ \frac{3}{4} } \times {side}^{2} \\ \\ \sqrt{ \frac{3}{4} } \times {10}^{2} \\ \\ \sqrt{ \frac{3}{4} } \times 10 \times 10 \\ \\ \sqrt{3} \times 25 \\ \\ \sqrt{75} \\ \\ prime \: factorisation \\ \\ 25\sqrt{3}$