Math, asked by mike64, 1 year ago

wah kaun si number hi jisko 7,9 and 11 se bhag dene par remainder 1,2,3 aaya ho

Answers

Answered by vipinsingh16091998

0

Answer:

Step-by-step explanation:

Answer 687

7,9,11 ka LCM = 693

1,2,3 ka LCM = 6

Then

693-6=687

687÷7 r = 1

687÷9 r = 3

687÷11 r

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