Question

Walk Frm one corner of basket ball court to its diagonal opposite corner along its side if the basketball court has the dimension of 15m×28m 1) what is its distance covered 2) wht is the displacement

Answer 1

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Answer 2

Answer:

The distance covered is 43 m and the displacement is 31.76 m.

Explanation:

Given that,

The dimension of basket ball court = 15 m×18 m

(I). Distance :

Distance is the length between the two points.

The distance covered is

$d = 15+28$

$d = 43\ m$

(II). Displacement :

Displacement is the shortest distance between the initial and final position.

The displacement is

Using Pythagorean theorem

$D =\sqrt{(15)^2+(28)^2}$

$D=31.76\ m$

Hence, The distance covered is 43 m and the displacement is 31.76 m.