Question

Walking 6/7th of his usual speed, a man is 12 minutes too late. the usual time taken by him to cover that distance is:

Answer 1

☆heya your answer is here☆

●New speed = (6/7) of usual speed.
New time = (7/6) of usual time.
Therefore (7/6 of usual time)- (usual time) = (1/5) hr.
=> (1/6 of usual time)= (1/5) hr 
=> usual time = (6/5) hr 
= 1 hr 12 min.

Answer 2

Answer:

The usual time taken by him to cover the distance is 72 minutes or 1 hour 12 minutes.

Step-by-step explanation:

Given : Walking 6/7th of his usual speed, a man is 12 minutes too late.

To find : The usual time taken by him to cover that distance ?

Solution :

Let the distance covered be 'x'.

Let the original speed be 'y'.

We know, $\text{Time}=\frac{\text{Distance}}{\text{Speed}}$

The original time taken is

$\text{Time}=\frac{x}{y}$

Walking 6/7th of his usual speed.

i.e. new speed is $\frac{6}{7}y$

New time is $\text{Time}=\frac{x}{\frac{6}{7}y}$

$\text{Time}=\frac{7x}{6y}$

A man is 12 minutes too late.

New time - Original time = 12

$\frac{7x}{6y}-\frac{x}{y}=12$

$\frac{x}{y}(\frac{7}{6}-1)=12$

$\frac{x}{y}(\frac{1}{6})=12$

$\frac{x}{y}=12\times 6$

$\frac{x}{y}=72$

Therefore, The usual time taken by him to cover the distance is 72 minutes or 1 hour 12 minutes.