Question

Walking at 3/4 of his normal speed abhishek is 16 minutes late in reaching his office

Answer 1

Step-by-step explanation:

Let s = his normal speed

t = his normal time

Then  

D = (3/4)s * (t+16)

Since the distance is the same we can equate this to his regular day which is D = s*t

s*t = (3/4)s * (t+16)

Time =48

Answer 2

Answer:

The answer is 48 mins.

Concept : when distance is constant speed is inversely proportional to time.

Step-by-step explanation:

We need to find the usual time taken by abhishek

let's consider Usual speed as U.S

New speed = U.S × (3/4)

Ratio: Usual speed : New speed is 4:3

Ratio: Usual Time : New time is 3:4 (as speed is inversely proportional to time)

let the Usual time be 3x  and  new time be 4x

so the difference in time is written as

4x - 3x = 16 mins

x = 16 mins

Usual time = 3x

                   = 3 × 16 ⇒ 48 mins

Usual time taken by abhishek to cover the distance between office and home is 48 mins.