Walking at 3/4 of his usual pace, a man reaches his office 20 minute late. Find his usual time?
Answers
Answered by
2
Answer:
60 minutes
Step-by-step explanation:
Let s = his normal speed
t = his normal time
Then
D = (3/4)s * (t+20)
Since the distance is the same we can equate this to his regular day which is D = s*t
s*t = (3/4)s * (t+20)
st = 3st/4 + 15s
st/4 = 15s
t = 60 minutes
Similar questions