Question

Walking at 3/4 of his usual speed a man is late by 1 1/2 hours the usual time is

Answer 1

ANSWER

16 hours 30 minutes

Explanation:

S1=s(let) T1=t hours(let)

S2=3s/4 T2=t+11/2 hours

=(2t+11)/2 hours

where S1,S2,T1 and T2 are initial speed, final speed, initial time and final time respectively.

Now,

S1T1=S2T2

or, sXt=3s/4X(2t+11)/2

or, t=3/8X(2t+11)

or, 8t/3=2t+11

or, 2t/3=11

or, 2t=33

or, t= 33/2=16.5=16 hours 30 minutes

Therefore,his initial time is 16 hours 30 minutes