Physics, asked by mukultanwar5985, 11 months ago

Walking at 4/7th of his usual speed ramu,gets late by 15 min find the time he would have taken walking at his usual speed

Answers

Answered by bangarambindu
6

Explanation:

W U

4 7----speed

7 4----time

diff 7-4=3

usual speed =15/3×4=20

Answered by vikashkumar08797
3

Answer:20 min

Explanation:

In both the cases the distance remains the same

Distance = speed * time

::Let the usual speed be S

::and Let the usual time be T

Then ,

According to problem

Walking 4/7 of his usual speed i.e (4/7)*S

He gets late by 15 min i.e (T+15)

Now we equating the distance as distance is same in both the cases

:: S*T = (4/7)*S * (T+15)

By solving we get T= 20 min.

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