walking at 5/6 of its usual speed, a train is 10 minutes too late. Find its usual time to cover the journey?
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let Speed be S and Time to cover the journey be T
S * T = D (distance of journey) --- 1
now as per the question stem we have
(5/6)S * (T + 10) = D ----2
Equating Value of D from (1) in (2) we get T = 50mins or 5/6hrs .
Ans D
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