walking at 5 km/hr, a student reached his school from his house 15 min early and walking at 3km/ hr, he is late by 9 min. what is distance between school and house
Answers
Step-by-step explanation:
t is time of school
t1 is time taken by student with speed 5 km/hr =5/60 km/min
t2 is time taken by student with speed 3 km/hr = 3/60 km/min
Now
relationship between t and t1,t2
t = t1+15
t1=t-15
t = t2-9
t2=t+9
now the distance between school and home d = time × speed
t1 × s1 = t2 × s2
(t-15)(5/60)=(t+9)(3/60)
5t-75=3t+27
2t=102
t=51min
now for t1
t= t1+15
51= t1+15
t1=36 min
d=t1×s1
d=36×5/60
d=180/60 km
d=3 km
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Answer:
3 km
Step-by-step explanation:
Let say Distance between home and school = 15D km
Time = Distance/Speed
Time taken with 5 km/hr = 15D/5 = 3D hr
Time time Taken with 3km /hr = 15D/3 = 5D
Difference between time = 5D - 3D = 2D hr
Difference in timing in reaching school = 9 - (-15) = 24 mins = 24/60 hrs
= 2/5 hrs
2D = 2/5
=> D = 1/5 km
Distance = 15D = 15 * (1/5) = 3km
the distance between his school and his house = 3 km
Answer:
the above answer is correct......