Question

Walking at a speed of 5kmph,lisa reaches office 10minutes late.if she walks at 10 kmph she reaches 5 min early.how far is her office

Answer 1

Hey there!

Lets us take the distance as ' x '

Speed1 = ( x ÷ 5 )

speed2 = ( x ÷ 10 )

The difference in time

⇒ 10 - ( -5 )

⇒ 15 minutes, which is ( 1 ÷ 4 ) hours

Difference in speeds =

( x ÷ 5 ) - ( x ÷ 10 ) = ( 1 ÷ 4 )

( 2x - x ) ÷ 10 = ( 1 ÷ 4 )

( x ÷ 10 ) = ( 1 ÷ 4 )

Cross multiplication :

4x = 10

x = 10 ÷ 4

x = 5 ÷ 2 km

⇒ 2.5 km

Hope my answer helps!

#BeBrainly

@sid071

Answer 2

Answer:

2.5km

Explanation:

D/5 - D/10 = 15/60

5D/50 = 15/60

THEN, D = 2.5KM