Question

walking at by 3/4 of his normal speed, a person reached office 20 minutes late. if he walked at normal speed then when will he reach office?

Answer 1

Let the distance be x km and speed be y km/h
Time taken by her to reach her office = x km/( y km/h) = x/y h
New speed = 3/4 of y km/h 3y/4 km/h
Time taken by her=x km/(3y/4 km/h) = 4x/3y h
A/q
(4x/3y - x/y) h=20/60 h
x/y=1
Therefore if she walk to her office at the normal speed then she would reach in 1 h.
Hope it helps!