Question

walking at the speed of 5 km per hour from his home,bikram reaches his school 5 min late, but walking at speed of 6 km per hour he reaches his home 5 mon equal, what is the distance of bikram's school from his home?

Answer 1

Answer:

A: The ruling equation here seems to be speed = distance divided by time.

Let T = time to reach school on time. Let D = distance to school.

Then, 6 = D / (T - 1/12) and 5 = D / T

so D = 6 (T - 1/12) and D = 5*T

Putting these two together, we get 6(T - 1/12) = 5*T

6T - 1/2 = 5T

and so T = 1/2 hour. If 5 = D/T then D = 5 * 1/2 = 2.5 km.

Unfortunately, the question is worded so that “5 minutes more” is needed at 5 km/hr. The unspoken question is, “more than WHAT”.

Following a suggestion from Victor Mazmanian, I offer another interpretation of the question, where 5 minutes more is meant to represent 5 minutes more than is required to get to school on time, rather than 5 minutes more than walking at 6 km/hr.

Here, instead of 5 = D/T we have 5 = D / (T +1/12) so D = 5 (T+1/12) and combine to

6(T- 1/12) = 5 (T + 1/12) and 6*T - 1/2 = 5*T + 5/12 so T = 11/12 (55 minutes) and

D = 6 * 11/12 - 1/2 = 5 km.

Step-by-step explanation:

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