Question

walking at the speed of 5km per hour from his home, bikram reaches his school 5 minutes late, but walking at speed of 6km per hour he reaches his school 5 minutes early. what is the distance of bikram's school from his home?

Answer 1

here the distance is constant

let the distance be 'x'kms

now at his first journey, time taken, t1 = $\frac{distance}{speed} =\frac{x}{5}$hours

at his second journey, time taken t2 = $\frac{x}{6}$

t1-t2=10 minutes, i.e 1/6 hours

∴$\frac{x}{5} -\frac{x}{6} =\frac{1}{6}$

solving, we get x=5kms