Question

walls of two buildings on either side of street are parallel to each other a ladder 6 long is placed on the street such that its top reaches the window of building at the height of 4 on turning the ladder over the other side of street its top touches the window of the Other building at the height the 4.3 metre find the breadth of the street​

Answer 1

Hey dude, here's ur ans

the base of the ladder is somewhere between the two buildings such that, when it touches one building, the point is 4units above the ground and when it touches the other building, its 4.3units above the ground.

So what we are gonna do is use Pythagoras theorem to find the length of the base in two cases then add it up.

1st case:

Let the base be of x units.

4²+x²=6² ( Pythagoras theorem)

x²=6²-4²

x²=36-16

x²=20

x=√20

x=2√5

2nd case:

4.3²+x²=6²

x²=6²-4.3²

x²=36-18.49

x²=17.51

x=√17.51

x=4.184 (approx.)

Therefore, width of street=

2√5+4.184=2×2.236+4.184

=4.472+4.184=8.656

Ans:8.656