Math, asked by Mylo2145, 1 year ago

wanna be a brainliezt....solve this

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Answers

Answered by kuldeep211003
3
my camera is not working presently so i have written steps to do it 
first: (x/a)(a^2/x)=a    i eq.
2.     (y/b)(y/b^2)=b    ii eq 
3.      (a+b)/c              iii eq
     x        y         -1
a/1    b/1    (a+b)/c     a/1
now cross multiply x y and -1


kuldeep211003: mark as branliest ans
Mylo2145: ok
Answered by Yaduvanshi12
3
Hello your answer,
In a attachment,
Attachments:

kuldeep211003: this is not cross multiplying method
Yaduvanshi12: Sorry i dont see which method you ask
Mylo2145: oh yes
Yaduvanshi12: Or any question
Yaduvanshi12: sorry its my mistake i really not see
Mylo2145: no problem
Yaduvanshi12: Okay
Yaduvanshi12: or any problem in math
Mylo2145: no
Mylo2145: its ok
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