Question

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Answer 1

Answer:-

√x^-1y × y^-1z × z^-1x=1

√1/x y × 1/y z × 1/z x=1

√Y/x × z/y × x/ z=1

The remains 1 =

√1=1

$\/$

Answer 2

Que no:-2

(x1/(a-b))1/(a-c) ×( x1/(b-c))1/(b-a) ×(x1/(c -a))1/(c -b) = x 1/(a - b)(a - c) × x 1/(b - c)(b - a) × x 1/(c - a)(c -b) = x 1/(a - b)(a - c) + 1/(b - c)(b - a) + 1/(c - a)(c -b) = x 1/(a - b)(a - c) - 1/(b - c)(a - b) - 1/(c - a)(b -c) = x 1/(a - b)(a - c) - 1/(b - c)(a - b) + 1/(a - c)(b -c) = x (b -c) - (a - c) + (a - b)/(a - b)(b -c)(a - c) = x (b -c - a + c + a - b)/(a - b)(b -c)(a - c) = x0/(a - b)(b -c)(a - c) = x0 = 1 Therefore, (x1/(a-b))1/(a-c) ×( x1/(b-c))1/(b-a) ×(x1/(c -a))1/(c -b) = 1

Que no:3

Hope it helps u^_^