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plzzz SOLVE....
In the given figure 'O' is the centre of the circle, if QR =OP and angle QRP =20 °. find the value of x and give reasons.
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OP=OQ (radii of same circle)
hence, OQ=QR (QR=OP given)
angle QOR=20°
angle OQR = 140° (angle sum property)
angle PQO=40° (straight line)
angle OPQ=40° (since OP=OQ)
angle POQ=100° (angle sum property)
angle x= 180° - (100°+20°)
angle x =60°
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Hope it helps you.
Pls mark it as brainlist ....
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tjjw13:
u r also right but she was fast sorry
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