WAP a program in java to print this series:
1-3+5-7+..............................up to n terms
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Program to find Sum of the series 1*3 + 3*5 + ….
Given a series:
Sn = 1*3 + 3*5 + 5*7 + …
It is required to find the sum of first n terms of this series represented by Sn, where n is given taken input.
Examples:
Input : n = 2
Output : S<sub>n</sub> = 18
Explanation:
The sum of first 2 terms of Series is
1*3 + 3*5
= 3 + 15
= 28
Input : n = 4
Output : S<sub>n</sub> = 116
Explanation:
The sum of first 4 terms of Series is
1*3 + 3*5 + 5*7 + 7*9
= 3 + 15 + 35 + 63
= 116
Let, the n-th term be denoted by tn.
This problem can easily be solved by observing that the nth term can be founded by following method:
tn = (n-th term of (1, 3, 5, … ) )*(nth term of (3, 5, 7, ….))
Now, n-th term of series 1, 3, 5 is given by 2*n-1
and, the n-th term of series 3, 5, 7 is given by 2*n+1
Putting these two values in tn:
tn = (2*n-1)*(2*n+1) = 4*n*n-1
Now, the sum of first n terms will be given by :
Sn = ∑(4*n*n – 1)
=∑4*{n*n}-∑(1)
Now, it is known that the sum of first n terms of series n*n (1, 4, 9, …) is given by: n*(n+1)*(2*n+1)/6
And sum of n number of 1’s is n itself.
Now, putting values in Sn:
Sn = 4*n*(n+1)*(2*n+1)/6 – n
= n*(4*n*n + 6*n – 1)/3
Now, Sn value can be easily found by putting the desired value of n.
Below is the implementation of the above approach:
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