WAP buzz no. in java by using user defined
Answers
Answer:
Explanation:
A number is said to be Buzz Number if it ends with 7 OR is divisible by 7.
The task is to check whether the given number is buzz number or not.
Examples:
Input : 63
Output : Buzz Number
Explanation: 63 is divisible by 7, one
of the condition is satisfied.
Input : 72
Output : Not a Buzz Number
Explanation: 72 % 7 != 0, 72 is neither
divisible by 7 nor it ends with 7 so
it is not a Buzz Number.
Recommended: Please try your approach on {IDE} first, before moving on to the solution.
// C++ program to check whether the
// given number is Buzz Number or not.
#include <cmath>
#include <iostream>
using namespace std;
// function to check BUzz number.
bool isBuzz(int num)
{
// checking if the number
// ends with 7 and is divisible by 7
return (num % 10 == 7 || num % 7 == 0);
}
// Driver method
int main(void)
{
int i = 67, j = 19;
if (isBuzz(i))
cout << "Buzz Number\n";
else
cout << "Not a Buzz Number\n";
if (isBuzz(j))
cout << "Buzz Number\n";
else
cout << "Not a Buzz Number\n";
}