wap in java to find the equivalent power of a number
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P = V^2/R ---> R = V^2/P = 200V^2/60W = 667Ω and because we have three light bulbs connected in series the total resistance is equal to 3*667 = 2kΩ so the total power is equal to P = 200V^2/2kΩ = 20W This means that the book give you the correct equation.
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