Question

Wap in python to find roots of a quadratic equation and its type(real, and eqaul , real and unequal)

Answer 1

Heya friend,

Here we go :

Before we move on to the code,

First let us understand about roots of the quadratic equation.

roots can be founded by discriminant method which we'll be using here :-

-b±$\sqrt{d}$  /  2a

where,

d = $b^{2} - 4ac$

and,

Now, Let's move on to the type of the equation :

if d=0   The roots are real and equal

if d > 0  The roots are real and unequal

if d<0    No real roots of the equation exist

NOTE :-

• We know, if a = 0, then the we do not consider the equation as quadratic, so we will use this concept in the program also.
• Here, we have to use the square root function which is a module function, for that we have to call that by calling the math module.

Now' let's see the code:

                         SOURCE CODE

#To find roots of a quadratic equation and it's type

a = float(input('coefficient of x^2 = '))

b = float(input('coeeficient of x = '))

c = float(input('Enter the constant term = '))

import math

if a==0:

   print('not a quadratic equation')

else:

   d=b**2-(4*a*c)

   if d==0:

       x1 = x2 = -b/(2*a)

       print('The roots are real and equal')

       print('The roots are :',x1,'and',x2)

   elif d>0:

       x1 = -b + math.sqrt(d)/(2*a)

       x2 = -b + math.sqrt(d)/(2*a)

       print('The roots are real and unequal')

       print('The roots are :',x1,'and',x2)

   else:

       print('No real roots of the quadratic equation exist')

=================================================

Now, for the output, I'll show the output for all the 4 cases when the roots are real and equal, real and unequal, no real roots and not a quadratic equation

=================================================

                              OUTPUT

coefficient of x^2 = 1

coeeficient of x = -4

Enter the constant term = 4

The roots are real and equal

The roots are : 2.0 and 2.0

>>>  

>>>  

coefficient of x^2 = 0

coeeficient of x = 1

Enter the constant term = 1

not a quadratic equation

>>>  

>>>  

coefficient of x^2 = 1

coeeficient of x = 1

Enter the constant term = -2

The roots are real and unequal

The roots are : 0.5 and 0.5

>>>  

>>>  

coefficient of x^2 = 1

coeeficient of x = 2

Enter the constant term = 3

No real roots of the quadratic equation exist

>>>

Thanks !

#BAL #answerwithquality

@MANAV

Answer 2

Answer:-

$\red{\fbox{\tt PROGRAM IN PYTHON LANGUAGE}}$

import math

a = float(input('Enter value of a = '))

b = float(input('Enter value of b = '))

c = float(input('Enter value of c = '))

if a==0:

   print('This is not a quadratic equation.')

else:

   d=b* *2-(4*a*c)

if d==0:

   x1 = x2 = -b/(2*a)

   print('The roots are real and equal.')

   print('The roots are :',x1,'and',x2)

elif d>0:

   x1 = -b + math.sqrt(d)/(2*a)

   x2 = -b + math.sqrt(d)/(2*a)

   print('The roots are real and unequal.')

   print('The roots are :',x1,'and',x2)

else:

   print('The Roots are imaginary and unequal.')      

$\orange{\tt Hope it will} \green{\tt help you.}$ ✨