Question

wap to accept a number and check if it disarium number or not ( in java)​

Answer 1

Answer:

WAP to accept a number and check if it disarium number or not

Explanation:

import java.util.Scanner;  

public class Example11 {  

   public static void main(String args[])

       {

           Scanner sc = new Scanner(System.in);

           System.out.print("Input a number : ");

           int num = sc.nextInt();

           int copy = num, d = 0, sum = 0;

           String s = Integer.toString(num);  

           int len = s.length();  

             

           while(copy>0)

           {

               d = copy % 10;  

               sum = sum + (int)Math.pow(d,len);

               len--;

               copy = copy / 10;

           }

             

           if(sum == num)

               System.out.println("Disarium Number.");

           else

               System.out.println("Not a Disarium Number.");

       }

   }

Output:

Input a number: 45                                                                                            

Not a Disarium Number.

Answer 2

${\huge{\sf{\red{\underline{\underline{ ÅÑSWËR}}}}}}$

Disarium number:-

Sum of the digit of number power by its own position in the number, generate a number.If this generated number equal to the original number this would be said disarium number.

Example:-

135

1¹+3²+5³

1+9+125

135

import java.util.*;

class disarium

{

public static void main( )

{

Scanner sc=new Scanner (System.in);

System.out.println("ENTER A NUMBER");

int n=sc.nextInt( );

int m=n;

int c=0;

while (n>0)

{

c++;

n=n/10;

}

int s=0;

while (m>0)

{

int r=m%10;

s=s+(int)Math.pow(r,c);

c--;

m=m/10;

}

if(s==on)

System.out.println(It is a disarium number);

else

System.out.println(It is not a disarium number);

}

}