Question

WAp to accept a number and check whether the number is armstrong or not.​

Answer 1

Explanation:

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Check Armstrong number for n digits

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public class Armstrong {

public static void main(String[] args) {

int number = 1634, originalNumber, remainder, result = 0, n = 0;

originalNumber = number;

for (;originalNumber != 0; originalNumber /= 10, ++n);

originalNumber = number;

for (;originalNumber != 0; originalNumber /= 10)

{

remainder = originalNumber % 10;

result += Math.pow(remainder, n);

}

if(result == number)

System.out.println(number + " is an Armstrong number.");

else

System.out.println(number + " is not an Armstrong number.");

}

}

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2nd program

Check Armstrong Number for 3 digit number

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public class Armstrong {

public static void main(String[] args) {

int number = 371, originalNumber, remainder, result = 0;

originalNumber = number;

while (originalNumber != 0)

{

remainder = originalNumber % 10;

result += Math.pow(remainder, 3);

originalNumber /= 10;

}

if(result == number)

System.out.println(number + " is an Armstrong number.");

else

System.out.println(number + " is not an Armstrong number.");

}

}

hope it helps

mark brainlist

Answer 2

An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is an Armstrong number since 3**3 + 7**3 + 1**3 = 371.