Question

wap to accept a number and check whether the number is a perfect sqaure or not.

Answer 1

Using which programming language... please specify

Answer 2

// Finding whether a number is a perfect square number in Java

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

public class PerfectSquareNumber {

     

   public static void main(String[] args) throws IOException{

       BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));

       System.out.print("Please enter an integer : ");

       int number = Integer.parseInt(reader.readLine());

         

       int sqrt = (int) Math.sqrt(number);

       if(sqrt*sqrt == number) {

           System.out.println(number+" is a perfect square number!");

       }

else {

           System.out.println(number+" is NOT a perfect square number!");

       }

         

   }

}

Hope this helps :)

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