wap to accept a number and display those digits of the number which are the factors of 5 in java
Answers
Answer:
class factors
{
static void main()
{
int a=5;
System.out.print("\n");
System.out.print("The factors are : ");
for(int i=1;i<=a/2;i++)
{
if(a%i==0)
System.out.print(i+",");
}
System.out.print(a);
}
}
Following are the program that is mention below.
Explanation:
import java.util.*; // import package
public class Main // main class
{
public static void main(String[] args) // main method
{
Scanner sc4=new Scanner(System.in); // scanner class
System.out.println("Enter the terms you want:");
int num1 = sc4.nextInt();// read input by user
int k; // variable declaration
for(k=5;k<=num1;k++) //iterating the loop
{
if(k%5==0) // checking condition
{
System.out.print(" " +k); // display value
}
}
}
}
Output:
Enter the terms you want: 50
5 10 15 20 25 30 35 40 45 50
Following are the description of program
- Create the object of scanner class in sc4 which is used for taking user input.
- Read the input in "num1" variable by the user.
- Itearting the loop and display the number which is factor of 5 by using the if statement .
Learn More:
- brainly.in/question/2323394