WAP to accept a word and check whether the word is palindrome or not.
for example- madam,dad, arora
(in java)
Answers
Answered by
4
import java.io.*;
class pal
{
public static void main()throws IOException
{
BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter a word");
String w,w1="",w2="";
w=in.readLine();
char ch;
int l,i;
l=w.length();
w1=w;
for(i=0;i<l;i++)
{
ch=w1.charAt(i);
w2=ch+w2;
}
if(w.equals(w2)==true)
S.o.pln("PALINDROME WORD="+w)
}
}
I hope it's correct....
class pal
{
public static void main()throws IOException
{
BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter a word");
String w,w1="",w2="";
w=in.readLine();
char ch;
int l,i;
l=w.length();
w1=w;
for(i=0;i<l;i++)
{
ch=w1.charAt(i);
w2=ch+w2;
}
if(w.equals(w2)==true)
S.o.pln("PALINDROME WORD="+w)
}
}
I hope it's correct....
Ashvi16:
can u do in any other method
Answered by
5
import java.io.*;
public class Palindrome
{
public static void main(String[] args) throws IOException
{
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
int i,l;
String s,p="";
System.out.print("Enter the word: ");
s = in.readLine();
l = s.length();
for(i=0;i<l;i++)
{
p=p+s.charAt(l-i-1);
}
if(s.equals(p))
{
System.out.println(s+" is a palindrome.");
}
else
{
System.out.println(s+" is not a palindrome.");
}
}
}
public class Palindrome
{
public static void main(String[] args) throws IOException
{
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
int i,l;
String s,p="";
System.out.print("Enter the word: ");
s = in.readLine();
l = s.length();
for(i=0;i<l;i++)
{
p=p+s.charAt(l-i-1);
}
if(s.equals(p))
{
System.out.println(s+" is a palindrome.");
}
else
{
System.out.println(s+" is not a palindrome.");
}
}
}
Similar questions
Social Sciences,
8 months ago
English,
8 months ago
Computer Science,
1 year ago
Chemistry,
1 year ago
English,
1 year ago