Question

WAP to calculate roots of quadratic equation ax2 + bx + c=0​

Answer 1

The best way to write this program is to directly use the quadratic formula

$\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

#Program by Ankitraj707

import math

# function for finding roots

def roots( a, b, c):

# calculating discriminant using formula

dis = b * b - 4 * a * c

sqrt_val = math.sqrt(abs(dis))

# checking condition for discriminant

if dis > 0:

$\: \: \: \:$ print(" real and different roots ")

$\: \: \: \:$ print((-b + sqrt_val)/(2 * a))

$\: \: \: \:$ print((-b - sqrt_val)/(2 * a))

elif dis == 0:

$\: \: \: \:$ print(" real and same roots")

$\: \: \: \:$ print(-b / (2 * a))

# when discriminant is less than 0

else:

$\: \: \: \:$ print("Complex Roots")

$\: \: \: \:$ print(- b / (2 * a), " + i", sqrt_val)

$\: \: \: \:$ print(- b / (2 * a), " - i", sqrt_val)

# Driver Program

a = 1

b = 10

c = -24

# If a is 0, then incorrect equation

if a == 0:

$\: \: \: \:$ print("Input correct quadratic equation")

else:

$\: \: \: \:$ roots(a, b, c)

#Keep asking such questions