WAP to display the value of discriminant of a quadratic equation.
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√b^2-4ac
Is the discriminant of a quadratic equation
Is the discriminant of a quadratic equation
Answered by
1
Quadratic Equation
#include <stdio.h>
#include <math.h>
int main()
{
double a, b, c, determinant, root1,root2, realPart, imaginaryPart;
printf("Enter coefficients a, b and c: ");
scanf("%lf %lf %lf",&a, &b, &c);
determinant = b*b-4*a*c;
// condition for real and different roots
if (determinant > 0)
{
// sqrt() function returns square root
root1 = (-b+sqrt(determinant))/(2*a);
root2 = (-b-sqrt(determinant))/(2*a);
printf("root1 = %.2lf and root2 = %.2lf",root1 , root2);
}
//condition for real and equal roots
else if (determinant == 0)
{
root1 = root2 = -b/(2*a);
printf("root1 = root2 = %.2lf;", root1);
}
// if roots are not real
else
{
realPart = -b/(2*a);
imaginaryPart = sqrt(-determinant)/(2*a);
printf("root1 = %.2lf+%.2lfi and root2 = %.2f-%.2fi", realPart, imaginaryPart, realPart, imaginaryPart);
}
return 0;
}
#include <stdio.h>
#include <math.h>
int main()
{
double a, b, c, determinant, root1,root2, realPart, imaginaryPart;
printf("Enter coefficients a, b and c: ");
scanf("%lf %lf %lf",&a, &b, &c);
determinant = b*b-4*a*c;
// condition for real and different roots
if (determinant > 0)
{
// sqrt() function returns square root
root1 = (-b+sqrt(determinant))/(2*a);
root2 = (-b-sqrt(determinant))/(2*a);
printf("root1 = %.2lf and root2 = %.2lf",root1 , root2);
}
//condition for real and equal roots
else if (determinant == 0)
{
root1 = root2 = -b/(2*a);
printf("root1 = root2 = %.2lf;", root1);
}
// if roots are not real
else
{
realPart = -b/(2*a);
imaginaryPart = sqrt(-determinant)/(2*a);
printf("root1 = %.2lf+%.2lfi and root2 = %.2f-%.2fi", realPart, imaginaryPart, realPart, imaginaryPart);
}
return 0;
}
souravChoudhary:
good
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