Computer Science, asked by kingtaehyung190, 3 months ago

Wap to enter a number which must be >9 and <100 and check if it is divisible by 3 ,5 or both 3 and 5 or not , using nested if .

Answers

Answered by anindyaadhikari13
3

\textsf{\large{\underline{Solution}:}}

The given problem is solved using language Java.

import java.util.Scanner;

public class Brainly{

   public static void main(String args[]){

       Scanner sc=new Scanner(System.in);

       System.out.print("Enter a number (10-99): ");

       int n=sc.nextInt();

       if(n%5==0){

           if(n%3==0)

               System.out.println("Number is divisible by both 5 and 3.");

           else

               System.out.println("Number is divisible by 5 but not by 3.");

       }

       else if(n%3==0)

           System.out.println("Number is divisible by 3 but not by 5.");

       else

           System.out.println("Number is neither divisible by 3 and 5.");

       sc.close();

   }

}

\textsf{\large{\underline{Sample I/O}:}}

#1

Enter a number (10-99): 25

Number is divisible by 5 but not by 3.

———————————————————————

#2

Enter a number (10-99): 12

Number is divisible by 3 but not by 5.

———————————————————————

#3

Enter a number (10-99): 15

Number is divisible by both 5 and 3.

———————————————————————

#4

Enter a number (10-99): 14

Number is neither divisible by 3 and 5.

Attachments:

anindyaadhikari13: Thanks for the brainliest :)
Similar questions