Question

WAP TO FIND THE LARGEST AND THE SECOND LARGEST ELEMENT IN A GIVEN LIST OF ELEMENT?

Answer 1

Explanation:

Answer:

Answer:Cl²⁺ + SO₂⁻+ 2H₂O -------> Cl⁻ + SO₄²⁻+ 4H⁺

Answer:Cl²⁺ + SO₂⁻+ 2H₂O -------> Cl⁻ + SO₄²⁻+ 4H⁺Explanation:

Answer:Cl²⁺ + SO₂⁻+ 2H₂O -------> Cl⁻ + SO₄²⁻+ 4H⁺Explanation:Cl²⁺ + 3e⁻ ------> Cl⁻  (equation i)

Answer:Cl²⁺ + SO₂⁻+ 2H₂O -------> Cl⁻ + SO₄²⁻+ 4H⁺Explanation:Cl²⁺ + 3e⁻ ------> Cl⁻  (equation i)SO₂⁻+2H₂O -------> SO₄²⁻ + 3e⁻ (equation ii)

Answer:Cl²⁺ + SO₂⁻+ 2H₂O -------> Cl⁻ + SO₄²⁻+ 4H⁺Explanation:Cl²⁺ + 3e⁻ ------> Cl⁻  (equation i)SO₂⁻+2H₂O -------> SO₄²⁻ + 3e⁻ (equation ii)Adding equation i and ii

Answer:Cl²⁺ + SO₂⁻+ 2H₂O -------> Cl⁻ + SO₄²⁻+ 4H⁺Explanation:Cl²⁺ + 3e⁻ ------> Cl⁻  (equation i)SO₂⁻+2H₂O -------> SO₄²⁻ + 3e⁻ (equation ii)Adding equation i and iiwe get

Answer:Cl²⁺ + SO₂⁻+ 2H₂O -------> Cl⁻ + SO₄²⁻+ 4H⁺Explanation:Cl²⁺ + 3e⁻ ------> Cl⁻  (equation i)SO₂⁻+2H₂O -------> SO₄²⁻ + 3e⁻ (equation ii)Adding equation i and iiwe get Cl²⁺ + SO₂⁻+ 2H₂O -------> Cl⁻ + SO₄²⁻+ 4H⁺