Wap to find the squareroot of an number in java without using inbuilt function??
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ber without using any built-in functions
Java Program
/*Java program to find out square root of a given number
* without using any Built-In Functions
*/
public class SquareRootDemo2
{
public static void main(String[] args)
{
//Number for which square root is to be found
double number = -12;
//This method finds out the square root
findSquareRoot(number);
}
/*This method finds out the square root without using
any built-in functions and displays it */
public static void findSquareRoot(double number)
{
boolean isPositiveNumber = true;
double g1;
//if the number given is a 0
if(number==0)
{
System.out.println("Square root of "+number+" = "+0);
}
//If the number given is a -ve number
else if(number<0)
{
number=-number;
isPositiveNumber = false;
}
//Proceeding to find out square root of the number
double squareRoot = number/2;
do
{
g1=squareRoot;
squareRoot = (g1 + (number/g1))/2;
}
while((g1-squareRoot)!=0);
//Displays square root in the case of a positive number
if(isPositiveNumber)
{
System.out.println("Square roots of "+number+" are ");
System.out.println("+"+squareRoot);
System.out.println("-"+squareRoot);
}
//Displays square root in the case of a -ve number
else
{
System.out.println("Square roots of -"+number+" are ");
System.out.println("+"+squareRoot+" i");
System.out.println("-"+squareRoot+" i");
}
}
}
pls mark me as brainlist
Java Program
/*Java program to find out square root of a given number
* without using any Built-In Functions
*/
public class SquareRootDemo2
{
public static void main(String[] args)
{
//Number for which square root is to be found
double number = -12;
//This method finds out the square root
findSquareRoot(number);
}
/*This method finds out the square root without using
any built-in functions and displays it */
public static void findSquareRoot(double number)
{
boolean isPositiveNumber = true;
double g1;
//if the number given is a 0
if(number==0)
{
System.out.println("Square root of "+number+" = "+0);
}
//If the number given is a -ve number
else if(number<0)
{
number=-number;
isPositiveNumber = false;
}
//Proceeding to find out square root of the number
double squareRoot = number/2;
do
{
g1=squareRoot;
squareRoot = (g1 + (number/g1))/2;
}
while((g1-squareRoot)!=0);
//Displays square root in the case of a positive number
if(isPositiveNumber)
{
System.out.println("Square roots of "+number+" are ");
System.out.println("+"+squareRoot);
System.out.println("-"+squareRoot);
}
//Displays square root in the case of a -ve number
else
{
System.out.println("Square roots of -"+number+" are ");
System.out.println("+"+squareRoot+" i");
System.out.println("-"+squareRoot+" i");
}
}
}
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