Question

wap to input array of n elements input another no.and check whether no.is present if present then print with actual position​

Answer 1

Answer:

import java.util.*;

class Search

{

public static void main()

{

Scanner sc=new Scanner(System.in);

System.out.println("Enter n ");

int a[]=new int[n];

int flag=0;

System.out.println("Enter "+n+" elements");

for(int i=0;i<n;i++)

a[i]=sc.nextInt();

System.out.println("Enter a number for searching");

int s=sc.nextInt();

for(int i=0;i<n;i++)

{

if(s==a[i])

{

System.out.println("Element found at "+(i+1));

flag=1;

break;

}

}

if(flag==0)

System.out.println("Element not found");

}

}

Thank you

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Answer 2

The following codes have been written using Python.

n = int(input("Enter the number of elements you'd like to enter: "))

l = list()

for i in range(n):

 x = eval(input("Enter the element: "))

 l.append(x)

print("The list you've entered: ", l)

c = eval(input("Enter the element you'd like to search for: "))

if c in l:

 print(c, "occurs first in", l.index(c))

• append() enables users to add elements to a list.
• index() displays the index position of an element's first occurence.