Question

wap to input N different numbers and display the sum of prime number


do this pls​

Answer 1

$\huge\red{\mid{\fbox{\tt{Using\: Python\: 3}}\mid}}$

def is_prime(n):

if n < 2:

return 0

if n <= 3:

return 1

if n % 2 == 0 or n % 3 == 0:

return 0

i = 5

while(i * i <= n) :

if n % i == 0 or n % (i + 2) == 0:

return 0

return 1

nums = list(map(int, input("enter nums: ").split()))

print("sum of primes:", sum([n for n in nums if is_prime(n)]))

$\large\mathsf\color{lightgreen}useful?\: \color{white}\longrightarrow\: \color{orange}brainliest!$

Answer 2

Required Answer:-

Question:

• Write a program to input n different numbers and display the sum of prime numbers.

Solution:

This is an easy question.Here is the code.

This is written in Java.

import java.util.*;

public class PrimeSum {

static boolean isPrime(int n) {

int c=0;

for(int i=1;i<=n;i++) {

if (n%i==0)

c++;

}

return (c==2);

}

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);

System.out.print("How many numbers?? ");

int n=sc.nextInt(), s=0;

System.out.println("\nEnter the numbers...");

for (int i=0;i<n;i++)

{

System.out.print("Enter: ");

int j=sc.nextInt();

if(isPrime(j))

s+=j;

}

System.out.println("Sum of all the prime numbers is: "+s);

sc.close();

}

}

This is written in Python.

def isPrime(x):

c=0

for i in range(1,x+1):

if x%i==0:

c=c+1

if c==2:

return True

else:

return False

n,s=int(input("how many numbers?? ")),0

print("Enter them...")

for i in range(0,n):

x=int(input("Enter: "))

if isPrime(x):

s+=x

print("Sum of all the prime numbers is: ",s)

★ I have created a function which checks if a number is prime or not. Then, I have taken n numbers as input. If the number entered is prime then it is added to s. The final result of s is the sum of all the prime numbers.

Output is attached.