Question

WAP to jnput the radius of the circle and print the area and circumference. take pie = 3.14​

Answer 1

$\huge\red{\mid{\fbox{\tt{Using\: Python\: 3}}\mid}}$

print("Area:", (pi := 3.14) * (r := float(input("r: "))) ** 2)

print("Circumference", 2 * pi * r)

$\large\mathsf\color{lightgreen}useful?\: \color{white}\longrightarrow\: \color{orange}brainliest!$

Answer 2

Program-s:

JAVA:

import java.util.Scanner;

public class Main

{ public static void main(String[] args) {

  Scanner scan =new  Scanner (System.in);

       System.out.println("Enter the radius: ");

       int r= scan.nextInt();

       System.out.println("The area: "+3.14*r*r)};

   System.out.println("The circumference: "+3.14*r*2);}

}

C++:

#include <iostream>

using namespace std;

int main() {

  int radius;

  cout << "Enter the radius: ";

  cin >> radius;

  cout << "The area is: " << 3.14*radius*radius << endl;

 cout << "The circumference is: " << 3.14*radius*2 << endl;

  return 0;  }

QBASIC:

CLS

INPUT "ENTER RADIUS: "; R

PRINT "THE AREA: "; 3.14*R*R

PRINT "THE AREA: "; 3.14*R*2

END

Python:

r=int(input("Enter radius: "))

print("The area:", 3.14*r*r)

print("The circumference:", 3.14*r*2)

C:

#include <stdio.h>

#include <math.h>

int main()

{   float r;

 printf("Enter the radius: ");

 scanf("%f", &r);

 printf("Area: %.2f",3.14159*r*r);

 printf("Circumference: %.2f",3.14159*r*2);

 return 0;  }