WAP TO STORE 10 NUMBERS IN A ARRAY A[] ABD 5 NUMBERS IN A ARRAY B[] AND THEN MERGE INTO ARRAY C []
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Answer:
#include<iostream.h>
#include<conio.h>
void input1(int a[],int n)
{
cout<<"\nEnter elements of first array ";
for(int i=0;i<n;i++)
{
cin>>a[i];
}
}
void input2(int b[i],int m)
{
cout<<"\nEnter elements of second array ";
for(int i=0;i<m;i++)
{
cin>>a[i];
}
}
void merge(int a[],int b[],int c[],int m, int n)
{
for(int i=0;i<n+m;i++)
{
if(i<n)
{
c[i]=a[i];
}
else
{
c[i]=b[i];
}
}
}
void show(int c[],int m, int n)
{
for(int i=0;i<n+m;i++)
cout<<c[i]<<endl;
}
void main()
{
clrscr();
int a[100],b[100],n,m,c[100];
cout<<"\n Enter size of array 1";
cin>>n;
cout<<"\N Enter size of array 2";
cin>>m;
input1(a,n);
input2(b,m);
merge(a,bc,m,n);
show(c,m,n);
getch();
}
The value of m and n in above program are:
n=10
m=5
(as given in the question)
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