WARNING IT'S A TOUGH QUESTION! A rectangular reservoir is 120m long and 75m wide.At what speed per hour must water flow into it through a square pipe of 20 cm wide so that the water rises by 2.4 m in 18 hours?
Answers
Answer:
30km/hr
Step-by-step explanation:
Given: Dimensions of reservoir are:
Length = 120 m.
Breadth = 75 m.
Height = 2.4 m.
∴ Volume of water in reservoir = length * breadth * height
= 120 * 75 * 2.4
= 21600 m³.
Let the speed of water flowing through the pipe be 'x' km/hr.
So, the distance traveled in 18 hours(d) = 18x.
Now,
∴ Volume of water in reservoir = Volume of water flows out of pipe
⇒ 21600 = (20 * 20 * 18x)/10000
⇒ 21600 * 10000 = 7200 * x
⇒ x = 30000 m/hr
(or)
⇒ x = 30 km/hr.
Therefore, Speed = 30 km/hr.
Hope it helps!
length of reservoir is 120m
breath of reservoir is 75m
the height of water level in 18hour =2.4m
volume of the reservoir 120x 75x 2.4
=21600mcube
let the speed of the water =xm/he
the water following in the pipe
width 20cm is 0.2m
and height 20cm is 0.2m
the length of cuboid is 18hrs =18xm
the volume of the water flows in 18hr
= 0.2 x 0.2 x 18x
=0.72 xm cube
volume of the water collected I .the reservoir= volume of the water flows out of the pipe in 18hrs
21600= 0.72x
x = 21600/0.72
x= 30000m/he
speed of the water is 30km /hr