was 32,000. It had increased by 5% and 3%,
Two years ago, the population of a town
.
respectively, in 1st year and 2nd year. Find its
present population.
Answers
Answered by
0
Answer:
The town will have a population of 42,320 in two years. ... annually at the rate of 10% p.a. What was its population 2 years ago? ... First year increase will be 15% of 32,000 = 4800.
Step-by-step explanation:
Let the population in 2006 be x.
Pop. in 2009=x×(1+
100
5
)
3
⇒1,38,915=x×(
20
21
)
3
⇒x=
9261
138915×8000
=120000
Answered by
0
Answer:
Two years ago,
population was 32000
In 1st year population increased by 5%
32000 * (5/100) = 1600
.•. 32000+1600=33600
this was the population in 1st year.
Likely ,
in 2nd year it was 34608.
therefore,
the present population = 32000 + population in 1st year + population in 2nd year
= 32000 + 33600 + 34608
= 100208
it is the present population of a town
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