Chemistry, asked by parikshit2525, 1 year ago

Wat equilibrium, PCI() = PC12(g) + Cl(a).)
the observed molecular weight of PCI, is 124 g
mol-1 at 250°C. The degree of dissociation
of PCI. at 250°C will be (Molar mass of
PCI5 = 208.5 g mol-')
(1) 46%
(2) 68%
(3) 54%
4) 42%​

Answers

Answered by Anonymous
0

Wat equilibrium, PCI() = PC12(g) + Cl(a).)

the observed molecular weight of PCI, is 124 g

mol-1 at 250°C. The degree of dissociation

of PCI. at 250°C will be (Molar mass of

PCI5 = 208.5 g mol-')

(1) 46%

(2) 68%✔️✔️✔️

(3) 54%

4) 42%

Answered by MarshmellowGirl
6

{\textbf{Answer}}

Wat equilibrium, PCI() = PC12(g) + Cl(a).)

the observed molecular weight of PCI, is 124 g

mol-1 at 250°C. The degree of dissociation

of PCI. at 250°C will be (Molar mass of

PCI5 = 208.5 g mol-')

(1) 46%

(2) 68%♥️♥️

(3) 54%

4) 42%

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