Question

wat is the unit digit of the sum of the first 99 whole numbers is.​

Answer 1

Answer:

0

Step-by-step explanation:

$1+2+3+.....+99 = \frac{99(100)}{2} = 99 \times 50$

Or

Observe

[(1+9)+(2+8)+(3+7)+(4+6)+5 ] 10 times

Answer 2

Answer:Let us write down first few factorials. 1. 1! = 1 2. 2! = 2 3. 3! = 6 4. 4! ... So , number at the units place in the sum of (1! + 2! + 3! + 4!) Will remain as ... What is the digit in the unit position of the integer 1!+2!+3!+…99? 1,038 Views.

Step-by-step explanation: