Watching from the top of a 30 m high tower, angle of depression of a stone on the ground is found to be 45, then the distance of the stone from the lease of the tower is ……..m.
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Answer:
The hight of the pole is 21.1 m
Step-by-step explanation:
Let the height of the pole be h and the distance between the pole and the tower be x.
It can be observed that,
tan 60° = 50
x
x = 50
√3
And ,
tan 45° = 50-h
x
1 = 50-h
x
50-h = x
50-h = 50
√3
h = 50 - 50
√3
h = 50 (√3-1)
√3
h = 21.1m
Therefore the height of the pole is 21.1m.
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