Question

Water and chlorobenzene are immiscible liquids there mixture boils at 89 degree Celsius under reduced pressure of 7. 7 x 10 ^ 4 Pascal the vapour pressure of pure water at 89 degree celsius is 7 into 10 power 4 Pascal weight percent of chlorobenzene in distillate is

Answer 1

Hey dear,

● Answer -
Weight percent of chlorobenzene = 7.913%



● Explanation -
Here water(1) is solvent and chlorobenzene is solute(2).

Mole fraction of chlorobenzene -
X2 = ∆P / P°
X2 = (7.7×10^4 - 7×10^4) / (7.7×10^4)
X2 = 0.091

Weight percent of chlorobenzene -
(W2/W)% = X2 × M2 / (M1 + M2)
(W2/W)% = 0.091 × 120 / (120 + 18)
(W2/W)% = 0.07913 = 7.913 %

Weight percent of chlorobenzene in distillate is 7.913% .

Hope thiz helps you.